
Nuclear energy in Portugal is very limited and strictly non-commercial. Portugal has one 1MW research reactor located in the National Nuclear Research Centre at Sacavém, which is in permanent shutdown state. Further nuclear energy activities are not planned in the near future. Other nuclear activities include medical. . 1948 to 1954Portugal first began developing nuclear energy in 1948, when the Instituto para a Alta Cultura (Superior Culture Institute) proposed the creation of a commission of geologists and physicists. . • . The Independent Commission for Radiological Protection and Nuclear Safety (CIPRSN), created by Decree Law 139/2005 of 17 August, is an independent body currently working towards the creation of a national regulatory authority. The President of the. [pdf]
Nowadays, Portugal is attempting to greatly increase its energy production from renewable resources, including hydro, wind and solar power. The only nuclear reactor that the country has is the same 1 MW research reactor that was activated in 1961.
Portugal does not have any nuclear installations under the CNS. However, there is a research reactor, the Portuguese Research Reactor “RPI”, currently in transition to decommissioning, and without any nuclear fuel or spent fuel. 2. Data on nuclear installations Portugal does not have any nuclear installations under the CNS.
During October 1952, the temporary Commission for Nuclear Energy Studies was created and formed a partnership with the Portuguese universities, becoming the first centers for nuclear energy research in Portugal, both pure and applied.
There is currently no nuclear fuel or spent fuel in Portugal, and there is no intention of resuming a nuclear programme at this time. The decommissioning plan for the RPI will have to be prepared by the operator and submitted to approval by APA. The CNS was signed by Portugal on the 3rd of October 1994.
This report gives an overview on the present Portuguese nuclear policy, legislation and new measures relating to Nuclear Safety and Radiation Protection. Portugal has no nuclear installations, as defined in the Convention on Nuclear Safety (CNS), and all exploration of uranium ore was terminated in the year 2000.
On 21 January 1957, the Portuguese Government gave green light for the acquisition of this equipment and the reactor went operational on 25 April 1961. In the period from 1961 up to now the reactor was almost always operational, with some reduced periods of shutdown.

When two or more than two resistors are connected in series as shown in figure their equivalent resistance is calculated by: REq = R1 + R2 + R3 +. Rn . when the resistors are in parallel configuration the equivalent resistance becomes: Where 1. REq is the equivalent resistance of all resistors (R1, R2, R3. Rn) Related Posts: 1.. . The delta (Δ) interconnection is also referred to as Pi interconnection & the wye (Y) interconnection is also referred to as Tee (T). [pdf]
This being a parallel circuit now, we know that voltage is shared equally by all components, so we can place the figure for total voltage (10 volts ∠ 0°) in all the columns: Now we can apply Ohm’s Law (I=E/Z) vertically to two columns in the table, calculating current through the resistor and current through the capacitor:
Total capacitance of the capacitor connected in parallel & series configuration are given below: When the capacitors are connected in series configuration the equivalent capacitance becomes: The capacitance sums up together when they are connected together in a parallel configuration CEq = C1 + C2 + C3 + Cn Where Related Posts:
When multiple capacitors are connected in parallel, you can find the total capacitance using this formula. C T = C 1 + C 2 + + C n So, the total capacitance of capacitors connected in parallel is equal to the sum of their values.
Parallel R-C circuit. Because the power source has the same frequency as the series example circuit, and the resistor and capacitor both have the same values of resistance and capacitance, respectively, they must also have the same values of impedance. So, we can begin our analysis table with the same “given” values:
Capacitors connected in series are equivalent to a single capacitor with a larger spacing between the plates. You can learn more about this with our parallel plate capacitance calculator. When multiple capacitors are added to a circuit in series, you can find the total capacitance using this formula.
The complex impedance (Z) (real and imaginary, or resistance and reactance) of a capacitor and a resistor in parallel at a particular frequency can be calculated using the following formulas. Where: f is the Frequency in Hz. C is the Capacitance in Farads. R is the Resistance in Ohms. X C is the Capacitive Reactance in Ohms.

Taking the three capacitor values from the above example, we can calculate the total equivalent capacitance, CTfor the three capacitors in series as being: One important point to remember about capacitors that are connected together in a series configuration. The total circuit capacitance ( CT ) of any number of. . Find the overall capacitance and the individual rms voltage drops across the following sets of two capacitors in series when connected to a 12V AC supply. 1. a) two capacitors each with a capacitance of 47nF 2. b) one capacitor. . Then to summarise, the total or equivalent capacitance, CT of a circuit containing Capacitors in Seriesis the reciprocal of the sum of the reciprocals of all of the individual capacitance’s added together. Also for capacitors. [pdf]
This capacitive reactance produces a voltage drop across each capacitor, therefore the series connected capacitors act as a capacitive voltage divider network. The result is that the voltage divider formula applied to resistors can also be used to find the individual voltages for two capacitors in series. Then:
We have seen here that a capacitor divider is a network of series connected capacitors, each having a AC voltage drop across it. As capacitive voltage dividers use the capacitive reactance value of a capacitor to determine the actual voltage drop, they can only be used on frequency driven supplies and as such do not work as DC voltage dividers.
The two capacitors which are connected in series have the capacitance values of 10uF and 22uF respectively. Here the circuit voltage is 10V,this voltage is distributed between both capacitors. In the series connection all the capacitors have same charge (Q) on it but the supply voltage (V S) is not same for all capacitors.
Because as we now know, the reactance of both capacitors changes with frequency (at the same rate), so the voltage division across a capacitive voltage divider circuit will always remain the same keeping a steady voltage divider.
Q=C/V, for series connection, the charge is constant for all capacitors. Capacitor and voltage are in an inversely proportional relation. The higher capacitor has less voltage. From dividing rule = 4.420Ω + 13.26Ω = 17.68 Ohms. It can be used to reduce voltage to measure high-level voltage. It can measure the resistance of the sensors.
But just like resistive circuits, a capacitive voltage divider network is not affected by changes in the supply frequency even though they use capacitors, which are reactive elements, as each capacitor in the series chain is affected equally by changes in supply frequency.
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